顺时针打印矩阵/90度旋转矩阵

思路:遍历框框

左上角 和右下角的点,可以确定一个矩阵。

左上角(tr,tc)

右下角(dr,dc);

public static void PrintMatrix(int [][] matrix){
int tr=0;
int tc=0;
int dr=matrix.length-1;
int dc=matrix[0].length-1;
while(tc<=dc&&tr<=dr){
知识兔
printEdge(matrix,tr++,tc++,dr--,dc--); } }
public static void printEdge(int[][] m, int tR, int tC, int dR, int dC) {
if (tR == dR) {
for (int i = tC; i <= dC; i++) {
System.out.print(m[tR][i] + " ");
}
} else if (tC == dC) {
for (int i = tR; i <= dR; i++) {
System.out.print(m[i][tC] + " ");
}
} else {
int curC = tC;
int curR = tR;
while (curC != dC) {
System.out.print(m[tR][curC] + " ");
curC++;
}
while (curR != dR) {
System.out.print(m[curR][dC] + " ");
curR++;
}
while (curC != tC) {
System.out.print(m[dR][curC] + " ");
curC--;
}
while (curR != tR) {
System.out.print(m[curR][tC] + " ");
curR--;
}
}
 

 旋转

public static void rotateEdge(int[][] m, int tR, int tC, int dR, int dC) {        int times = dC - tC;         int tmp = 0;        for (int i = 0; i != times; i++) {            tmp = m[tR][tC + i];            m[tR][tC + i] = m[dR - i][tC];            m[dR - i][tC] = m[dR][dC - i];            m[dR][dC - i] = m[tR + i][dC];            m[tR + i][dC] = tmp;        }    }    public static void printMatrix(int[][] matrix) {        for (int i = 0; i != matrix.length; i++) {            for (int j = 0; j != matrix[0].length; j++) {                System.out.print(matrix[i][j] + " ");            }            System.out.println();        }    }

计算机